Answer :

Given that -2 is the zero of the polynomial.

So x = -2 which is x + 2 = 0



The other zeroes are as follows:


x2 + 11x + 10 = 0


Solving the above quadratic equation.


Sum = 11


Product = 10


So the numbers which satisfy the above condition are 10 and 1


x2 + 10x + x + 10 = 0


x(x + 1)+ 10(x + 1) = 0


(x + 10) (x + 1) = 0


Solving the first part,


x + 10 = 0


x = -10


Solving the second part,


x + 1 = 0


x = -1


Therefore the other zeroes of the polynomials are -1 and -10.


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