With the followin

Given that 2 + √3 and 2 - √3 are the zeroes of the given polynomial.

So (x – (2 + √3)) (x – (2 - √3)) = (x – 2 - √3) (x – 2 + √3)

= x² – 2x + √3x – 2x + 4 – 2√3 - √3x + 2√3 – 3

= x² – 4x + 1

The other zeroes are as follows:

x² – 2x - 35 = 0

Solving the above quadratic equation.

Sum = -2

Product = -35

So the numbers which satisfy the above condition are -7 and 5

x² – 7x + 5x - 35 = 0

x(x – 7) + 5(x – 7) = 0

(x + 5) (x – 7) = 0

Solving the first part,

x + 5 = 0

x = -5

Solving the second part,

x – 7 = 0

x = 7

Therefore the other zeroes of the polynomials are -5 and 7.