Q. 2 D3.5( 29 Votes )

# Find the zeroes of the given polynomials.

p(x)=x^{4} - 16

Answer :

p(x) = 0

⇒ x^{4} – 16 = 0

⇒ (x^{2} – 4)(x^{2} + 4)= 0

⇒ (x + 2)(x – 2)(x^{2} + 4)= 0

⇒ x = -2, x = 2 and x^{2} = 4

⇒ x = -2, x = 2 and x = ±2

Hence, x=2 and x=-2 are the zeroes of the polynomial.

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