Q. 1 D5.0( 4 Votes )

Solve the followi

Answer :

The given equations are


= – 2 … (1)


+ = 13 … (2)


Let a = and b =.


5a – 4b + 2 = 0 … (3)


2a + 3b – 13 = 0 … (4)


For cross multiplication method, we write the coefficients as



Hence, we get = =


= =


= =


a = = 2


b = = 3


When a = 2, = 2. Thus, x = 1/2.


When b = 3, = 3. Thus, y =.


(,) is the solution to the given system.


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