Q. 1 C5.0( 5 Votes )

Solve the followi

Answer :

The given equations are


= – 2 … (1)


+ = … (2)


By taking LCM,


(1) becomes 9x – 10y + 12 = 0


(2) becomes 2x + 3y – 13 = 0


For cross multiplication method, we write the coefficients as



Hence, we get = =


= =


= =


x = = 2


y = = 3


(2, 3) is the solution to the given system.


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