Answer :

The given equations are

– = – 2 … (1)

+ = … (2)

By taking LCM,

(1) becomes 9x – 10y + 12 = 0

(2) becomes 2x + 3y – 13 = 0

For cross multiplication method, we write the coefficients as

Hence, we get = =

⇒ = =

⇒ = =

⇒ x = = 2

⇒ y = = 3

∴ (2, 3) is the solution to the given system.

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