# The value of c fo

Condition for infinitely many solutions

a1/a2 = b1/b2 c1/c2 …(i)

The given lines are cx - y - 2 = 0 and 6x - 2y - 3 = 0;

Comparing with ax + by + c = 0;

Here, a1 = c, b1 = - 1, c1 = - 2

and a2 = 6, b2 = - 2,c2 = - 3

From Eq. (i),

Here, c/6 = -1/- 2

Also c/6 = -2/- 3

Solving, we get, c = 3 and c = 4.

Since, c has different values and so it’s not possible.

Hence, for no value of c the pair of equations will have infinitely many solutions.

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