# The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 3 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically.

We need to form linear equations for the situations.
Let cost of one bat = Rs. x

Let cost of one ball = Rs. y

In first case, three bats and 6 balls cost him 3900 rupees. therefore our equation becomes

⇒ 3x + 6y = 3900 ........(i)

Dividing equation by 3 both side

⇒ x + 2y = 1300

⇒ x = 1300 - 2y

For plotting the equation of graph, take different values of y and obtain the value of x from equation or you can do vice versa
At y = 0
⇒ x = 1300 - 2(0)
⇒ x = 1300
Now finding the value at x = 0
⇒ 0 = 1300 - 2y
⇒ 2y = 1300
⇒ y = 650

From above points, we make the graph as follows [Graphic representation]

In second case he buys one bat and 3 balls for 1300, therefore,

⇒ x + 3y = 1300 ......(ii)           [Algebraic representation]

⇒ x = 1300 - 3y

At y = 400
⇒ x = 1300 - 3(400)
⇒ x = 100

At y = 300
⇒ x = 1300 - 3(300)
⇒ x = 400

From above points, we make the graph as follows, [Graphical representation]

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