Answer :
To find the zeros of the polynomial let us first solve the polynomial by equating it to zero. Factorizing the given polynomial
4x2 – 4x + 1 = 0
To factorize the polynomial we have,
Sum of the value should be equal = -4
Product should be equal to = 4 × 1
= 4
So two numbers are -2, -2
4x2 – 2x – 2x + 1 = 0
2x(2x – 1) – 1(2x – 1) = 0
(2x-1)(2x-1) = 0
2x-1 = 0 or 2x-1 = 0
Both the parts are same.
Solving them,
2x-1 = 0
2x = 1
x = 1/2
When we compare the above quadratic equation with the generalized one we get,
ax2 + bx + c = 0
∴ a = 4, b = -4, c = 1
Sum of zeroes = -b / a
= - (-4) / 4
= 1
Product of zeroes = c / a
= 1 / 4
= 1/4
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