Answer :

To find the zeros of the polynomial let us first solve the polynomial by equating it to zero. Factorizing the given polynomial

4x^{2} + 8x = 0

4x(x + 8) = 0

4x = 0 or x + 8 = 0

Now solving the first part,

4x = 0

x = 0/4

x = 0

Now solving the second part,

x + 8 = 0

x = -8

When we compare the above quadratic equation with the generalized one we get,

ax^{2} + bx + c = 0

∴ a = 4, b = 8, c = 0

Sum of zeroes = -b / a

= -8 / 4

= -2

Product of zeroes = c / a

= 0 / 4

= 0

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