Q. 8

Prove: - sec 4A(1

Answer :

Formula used: -


(i) sec2A – tan2A = 1


(ii)


(iii)


(iv) (a2 – b2) = (a + b)(a – b)


taking L.H.S


Sec4A(1 – sin4A) – 2tan2A = sec4A – sec4Asin4A – 2tan2A


using formula (ii)



using formula (iii)


Sec4A(1 – sin4A) – 2tan2A = ((sec2A)2 – (tan2A)2) – 2tan2A


using formula (iv)


Sec4A(1 – sin4A) – 2tan2A = (sec2A + tan2A)(sec2A – tan2A) – 2tan2A


using formula (i)


Sec4A(1 – sin4A) – 2tan2A = sec2A + tan2A – 2tan2A = sec2A – tan2A


Sec4A(1 – sin4A) – 2tan2A = 1


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses