FalseExplanation:We have, sin4θ – 2sin2θ – 1 = 0Now,⇒ sin2θ = 1±√2⇒ sin2θ = 1+√2 or 1-√2We know that, -1≤ sin θ ≤ 1⇒ sin2θ ≤ 1but sin2θ = 1+√2 or 1-√2Which is not possible.Hence, the above statement is false.

Q. 725.0( 1 Vote )

True and False<br

Class 11th Mathematics - Exemplar 3. Trigonometric Functions

Answer :

False

Explanation:

We have, sin⁴θ – 2sin²θ – 1 = 0

Now,

⇒ sin²θ = 1±√2

⇒ sin²θ = 1+√2 or 1-√2

We know that, -1≤ sin θ ≤ 1

⇒ sin²θ ≤ 1

but sin²θ = 1+√2 or 1-√2

Which is not possible.

Hence, the above statement is false.

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