Answer :

We have, 3(sin x – cos x)4 + 6 (sin x + cos x)2 + 4(sin6 x + cos6 x)

=3(sin2x+cos2x-2sin x cos x)2+6(sin2x+cos2x+2sin x cos x) +4[(sin2x)3 + (cos2x)3]

=3(1-2sin x cos x)2+6(1+2sin x cos x) +4[(sin2x+ cos2x)3 -3 sin2x cos2x(sin2x+ cos2x)]

=3(1+4 sin2x cos2x-4sin x cos x) +6+12sin x cos x+4-12sin2x cos2x

=3+12 sin2x cos2x-12 sin x cos x+6+12sin x cos x+4-12sin2x cos2x


= 13

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

True and False<brMathematics - Exemplar

Find the values oRD Sharma - Mathematics

Prove that :
RD Sharma - Mathematics

The value of cos<Mathematics - Exemplar

The value of sin Mathematics - Exemplar

cos 2θ cos 2<spanMathematics - Exemplar

The value of <spaMathematics - Exemplar

If <span lang="ENMathematics - Exemplar

If <span lang="ENMathematics - Exemplar

Fill in the blankMathematics - Exemplar