A train cov

Let the speed of train be s km/hr as for “d” km it would take “t” hr.

We know that, Distance = Speed × Time

Therefore, d = s × t

According to question, for the same distance d,if speed increases by 10km/hr

time will decrease by 2hr,i. e,

d = (s + 10)(t – 2)

d = st – 2s + 10t – 20

2s – 10t = – 20

s – 5t = – 10 ……(i)

Also, for the same distance d, if speed decreases by 10/hr time will increase by 3hr,i. e,

d = (s – 10)(t + 3)

d = st + 3s – 10t – 30

3s – 10t = 30 …… (ii)

(i)&(ii) are the required equations.

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