Q. 325.0( 2 Votes )

Prove that: <span

Answer :

Formula: -


(i) sin (A + B) sin (A – B) = sin2 A – sin2 B


(ii)


(iii) 3sinA – 4sin3A = sin3A


Taking L.H.S we get,


sin A sin (60° – A) sin (60° + A) = sin A (sin2 60° – sin2 A) using formula (i)


sin A sin (60° - A) sin (60° + A) using formula (ii)


sin A sin (60° - A) sin (60° + A)


sin A sin (60° - A) sin (60° + A)


sin A sin (60° - A) sin (60° + A)


using formula (iii)


LH.S = R.H.S


Hence, Proved.


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