Answer :

Given,


m sin θ = n sin (θ + 2α)


To prove: tan (θ + α)cot α =


m sin θ = n sin (θ + 2α)



Applying componendo-dividendo rule –



By transformation formula of T-ratios we know that –


sin A + sin B =


and sin A – sin B =


On applying formula, we get –




{ tan x = (sin x)/(cos x)}


tan (θ + α) cot α =


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