Answer :

Given,


cos (θ + ϕ) = m cos (θ – ϕ)


To prove:


cos (θ + ϕ) = m cos (θ – ϕ)



Applying componendo – dividend, we get



From transformation formula, we know that –


cos(A+B) + cos(A – B) = 2cosAcosB


cos(A – B) – cos(A + B) = 2sinA sinB



{ (cos θ)/(sin θ) = cot θ }




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