Answer :

Given,



{ sin2θ + cos2θ = 1}


1 = 2 cosec θ sin θ cos θ


1 = 2 cos θ { sin θ cosec θ = 1}


cos θ = 1/2 = cos(π/3)


solution of cos x = cos α is given by


x = 2mπ ± α m Z


θ = 2nπ ± π/3, n Z


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