Answer :

Given: perimeter of one square = 40 m

Let length of square = a1


Then 4a1 = 40m


a1 = 10m


Area of square = a1 × a1


= 10 × 10


= 100m2


perimeter of second square = 96 m


Let length of square = a2


Then 4a2 = 96m


a2 = 24m


Area of square = a2 × a2


= 24 × 24


= 576m2


Because, perimeter of another square equal in area to the sum of the first two squares.


Hence,


area of another square = 100 + 576 = 676m


Area of square = a3 × a3


676 = (a3)2


a3 = 26m


Hence, perimeter = 4a3


= 4 × 26 = 104m


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