Q. 1404.8( 5 Votes )

# The perimeters of

Given: perimeter of one square = 40 m

Let length of square = a1

Then 4a1 = 40m

a1 = 10m

Area of square = a1 × a1

= 10 × 10

= 100m2

perimeter of second square = 96 m

Let length of square = a2

Then 4a2 = 96m

a2 = 24m

Area of square = a2 × a2

= 24 × 24

= 576m2

Because, perimeter of another square equal in area to the sum of the first two squares.

Hence,

area of another square = 100 + 576 = 676m

Area of square = a3 × a3

676 = (a3)2

a3 = 26m

Hence, perimeter = 4a3

= 4 × 26 = 104m

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