Q. 6

# An urn contains 5 white and 8 black balls. Two successive drawings of 3 balls at a time are made such that the balls drawn in the first draw are not replaced before the second draw. Find the probability that the first draw gives 3 white balls and the second draw gives 3 black balls.

Given: An urn containing 5 white and 8 black balls .Each trial is independent of the other trial.

To find: the probability that the first draws gives 3 white and the second draw gives 3 black balls.

Let , success in the first draw be getting 3 white balls.

Now , the Probability of success in the first trial is

P1(success) = = =

Let success in the second draw be getting 3 black balls.

Probability of success in the second trial without replacement of the first draw is given by

P2(success) = = =

Hence , the probability that the first draws gives 3 white and the second draw gives 3 black balls,with each trial being independent is given by

P1 P2 = =

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Probability of occurrence of an event | Quiz Time45 mins
Probability of occurrence of an event45 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses