Answer :

Given: A box containing 30 bulbs of which 5 are defective.Each trail is independent of the other trial.


To find: the probability that both the bulbs are chosen are defective.


Let , success :bulb chosen is defective .i.e


Now , the Probability of success in the first trial is


P1(success) =


Probability of success in the second trial without replacement of the first draw is given by


P2(success) =


Hence , the probability that both the bulbs are chosen are defective,with each trial being independent is given by


P1 P2 = =


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