Q. 163.7( 3 Votes )

The probabilities of A, B, C solving a problem are 1/3, 1/4 and 1/6, respectively. If all the three try to solve the problem simultaneously, find the probability that exactly one of them will solve it.

Answer :

Given : let A , B and C be three students whose chances of solving a problem is given i.e , P(A) = , P(B) = and P(C) = .


P() = , P() = and P()=


To Find: The probability that excatly one of them will solve it .


Now, P(excatly one of them will solve it) = P(A and not B and not c) +P (B and not A and not C) +P (C and not A and not B)


= P( A ) + P(B ) + P(C )


= P(A) P() P() + P(B) P() P() + P(C) P() P()


= [] + [] + []


= + +


=


Therefore , The probability that excatly one of them will solve the problem is


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Probability of occurrence of an event | Quiz TimeProbability of occurrence of an event | Quiz TimeProbability of occurrence of an event | Quiz Time45 mins
Probability of occurrence of an eventProbability of occurrence of an eventProbability of occurrence of an event45 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses