Answer :

A die thrown twice will have a total outcome of 6^{2}=36.

Let P(A) be the probability of getting the number 5 at least once.

Let P(B) be the probability of getting sum = 8.

The sample space of B = {(2,6),(3,5),(4,4),(5,3),(6,2)}

Let be the probability of getting the number 5 at least once and the sum equal to 8

The sample space of

*Tip – By conditional probability,* *where* *is the probability of occurrence of the event A given that B has already occurred.*

The probability that the number 5 have appeared at least once given that the sum = 8:

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