Q. 45.0( 3 Votes )

# Find the eq

Answer :

Since the planes are parallel to x + 2y – 2z + 8 = 0, they must be of the form:

x + 2y – 2z + θ = 0

We know, the distance of point (x1,y1,z1) from the plane

is given by:

According to the question, the distance of the planes from (2, 1, 1) is 2 units.

or

θ = 4 or –8

The required planes are:

x + 2y – 2z + 4 = 0 and x + 2y – 2z – 8 = 0

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