Q. 1

# Evaluate the following limits: As we need to find We can directly find the limiting value of a function by putting the value of the variable at which the limiting value is asked if it does not take any indeterminate form (0/0 or ∞/∞ or ∞-∞, .. etc.)

Let Z we need to take steps to remove this form so that we can get a finite value.

Tip: Similar limit problems involving trigonometric ratios are mostly solved using sandwich theorem. So to solve this problem we need to have a sin term so that we can make use of sandwich theorem.

Note: While modifying be careful that you don’t introduce any zero terms in the denominator

As, Multiplying numerator and denominator by 1-cos x, We have- Z = {As 1-cos2x = sin2x}

Z =    To apply sandwich theorem, we need to have limit such that variable tends to 0 and following forms should be there Here x π so we need to do modifications before applying the theorem.

As, sin (π-x) = sin x or sin (x - π) = -sin x and tan(π – x) = -tan x

we can say that-

sin2x = sin2(x-π) and tan2x = tan2(x-π)

As x π

(x – π) 0

Let us represent x - π with y

Z = Dividing both numerator and denominator by y2

Z = Z = {Using basic limits algebra}

As, Z =  Rate this question :

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