Q. 14.7( 3 Votes )

Find the equation

Answer :

Given Eq. of plane is 2x – 3y + z = 0 …… (1)

We know that equation of a plane parallel to given plane (1) is


2x – 3y + z + k = 0 …… (2)


As given that , plane (2) is passing through the point (1, – 1,2) so it satisfy the plane (2),


2(1) – 3( – 1) + (2) + k = 0


2 + 3 + 2 + k = 0


7 + k = 0


k = – 7


put the value of k in equation (2),


2x – 3y + z – 7 = 0


So, equation of the required plane is , 2x – 3y + z = 7


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