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# Find the direction cosines of the unit vector perpendicular to the plane + 1 = 0 passing through the origin.

The given plane equation is   Now, we calculate the magnitude of the vector .   On dividing both sides of the plane equation by 7, we get  Recall that the equation of the plane in normal form is given by where is a unit vector perpendicular to the plane through the origin.

So, here This is a unit vector normal to the plane .

Thus, the direction cosines of the unit vector perpendicular to the given plane are .

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Find the coordinate of the point P where the line through and crosses the plane passing through three points and Also, find the ratio in which P divides the line segment AB.

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