Q. 84.0( 6 Votes )

Find the ve

Answer :

Let the equation of the plane be …… (1)

Plane is passing through (3, 4, 2) and (7, 0, 6)




Required plane is perpendicular to 2x – 5y – 15 = 0



2b = 5a





Solving the above equations


a = 3.4 = , b = 8.5 = and


substituting the values in (1)




5x + 2y – 3z = 17




Vector equation of the plane is


The line passes through B(1, 3, – 2)


5(1) + 2(3)—3(– 2) = 17


The point B lies on the plane .


the line lies on the plane


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