Answer :

Given :


Equation of plane : 4x – 3y + 2z = 12


To Find :


1) Equation of plane in intercept form


2) Intercepts made by the plane with the co-ordinate axes.


Formula :


If


is the equation of plane in intercept form then intercept made by it with co-ordinate axes are


X-intercept = a


Y-intercept = b


Z-intercept = c


Answer :


Given equation of plane:


4x – 3y + 2z = 12


Dividing above equation throughout by 12




This is the equation of plane in intercept form.


Comparing above equation with



We get,


a = 3


b = -4


c = 6


Therefore, intercepts made by plane with co-ordinate axes are


X-intercept = 3


Y-intercept = -4


Z-intercept = 6


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