Answer :

Given :


Point : (-3, 2, 0)


To Find : equation of plane


Formula :


1) Equation of plane :


Equation of plane passing through point A with position vector and perpendicular to vector is given by,



Where,


Answer :


Position vector for given point A ≡ (-3, 2, 0) is



As required plane is parallel to YZ plane, therefore X-axis is perpendicular to the plane.



Therefore, equation of plane is






This is required equation of plane.


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