Point : (4, -2, 3)
To Find : equation of plane
1) Equation of plane :
Equation of plane passing through point A with position vector and perpendicular to vector is given by,
Position vector for given point A ≡ (4, -2, 3) is
As required plane is parallel to XY plane, therefore Z-axis is perpendicular to the plane.
Therefore, equation of plane is
This is required equation of plane.
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