Answer :

Given :


Equation of plane : 3x + 4 = 0


To Find : Direction cosines of the normal i.e.


Formula :


1) Direction cosines :


If a, b & c are direction ratios of the vector then its direction cosines are given by





Answer :


For the given equation of plane


-3x = 4


Direction ratios of normal vector are (-3, 0, 0)





= 3


Therefore, direction cosines are






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