Answer :

Given : Equations of lines -




To Find : Equation of plane.


Formulae :


1) Cross Product :


If are two vectors




then,



2) Dot Product :


If are two vectors




then,



3) Equation of plane :


If two lines are coplanar then equation of the plane containing them is



Where,


Given equations of lines are




Let,


Where,






Now,





Therefore,



= 6 – 56 – 48


= - 98


………eq(1)


Equation of plane containing lines is



Now,



From eq(1)



Therefore, equation of required plane is




This vector equation of plane.


As



= 6x – 28y + 12z


Therefore, equation of plane is


6x – 28y + 12z = -98


6x – 28y + 12z + 98 = 0


This Cartesian equation of plane.


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