Answer :
Given - &
are two lines to which a plane is parallel and it passes through the point
To find – The equation of the plane
Tip – A plane parallel to two vectors will have its normal in a direction perpendicular to both the vectors, which can be evaluated by taking their cross product
The equation of the plane maybe represented as 5x + 2y - 3z + d = 0
Now, this plane passes through the point (3, 4, 2)
Hence,
5 × 3 + 2 × 4 – 3 × 2 + d = 0
⇒ d = - 17
The Cartesian equation of the plane : 5x + 2y - 3z - 17 = 0 i.e. 5x + 2y - 3z = 17
The vector equation :
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