Q. 9

# Find the distance between the planes x + 2y + 3z + 7 = 0 and 2x + 4y + 6z + 7 = 0.

Formula : The distance between two parallel planes, say

Plane 1:ax + by + cz + d1 = 0 &

Plane 2:ax + by + cz + d2 = 0 is given by the formula where ( ) are constants of the planes

Therefore ,

First Plane x + 2y + 3z + 7 = 0

2(x + 2y + 3z + 7) = 0

2x + 4y + 6z + 14 = 0 …… (1)

Second plane 2x + 4y + 6z + 7 = 0 …… (2)

Using equation (1) and (2)

Distance between both planes    Rate this question :

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