Formula : Plane = r . (n) = d
Where r = any random point
n = normal vector of plane
d = distance of plane from origin
If two planes are parallel , then their normal vectors are same.
Parallel Plane 2x – 3y + 7z + 13 = 0
Normal vector = (2i - 3j + 7k)
∴ Normal vector of required plane = (2i - 3j + 7k)
Equation of required plane r . (2i - 3j + 7k) = d
In cartesian form 2x - 3y + 7z = d
Plane passes through point (0,0,0) therefore it will satisfy it.
2(0) - (0) + 3(0) = d
d = 0
Equation of required plane 2x - 3y + 7z = 0
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