Q. 83.5( 6 Votes )

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Answer :

To find: Differentiation of (3x – 5) (4x2 – 3 + ex)


Formula used: (i) (uv)′ = u′v + uv′ (Leibnitz or product rule)


(ii)


(iii)


Let us take u = (3x – 5) and v = (4x2 – 3 + ex)




Putting the above obtained values in the formula :-


(uv)′ = u′v + uv′


[(3x – 5)(4x2 – 3 + ex)]’ = 3×(4x2 – 3 + ex) + (3x – 5)×(8x + ex)


= 12x2 – 9 + 3ex+ 24x2 + 3xex – 40x - 5ex


= 36x2 + x(3ex – 40) – 9 - 2ex


Ans) 36x2 + x(3ex – 40) – 9 - 2ex


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