Q. 44.8( 5 Votes )

Differentiate:

xn cot x

Answer :

To find: Differentiation of xn cot x


Formula used: (i) (uv)′ = u′v + uv′ (Leibnitz or product rule)


(ii)


(iii)


Let us take u = xn and v = cotx




Putting the above obtained values in the formula :-


(uv)′ = u′v + uv′


(xn cotx)’ = nxn-1× cotx + xn× -cosec2x


= nxn-1cotx - xncosec2x


= xn (nx-1cotx - cosec2x)


Ans) xn (nx-1cotx - cosec2x)


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