Q. 44.8( 5 Votes )


xn cot x

Answer :

To find: Differentiation of xn cot x

Formula used: (i) (uv)′ = u′v + uv′ (Leibnitz or product rule)



Let us take u = xn and v = cotx

Putting the above obtained values in the formula :-

(uv)′ = u′v + uv′

(xn cotx)’ = nxn-1× cotx + xn× -cosec2x

= nxn-1cotx - xncosec2x

= xn (nx-1cotx - cosec2x)

Ans) xn (nx-1cotx - cosec2x)

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses