Q. 34.2( 5 Votes )

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Answer :

To find: Differentiation of ex cot x


Formula used: (i) (uv)′ = u′v + uv′ (Leibnitz or product rule)


(ii)


(iii)


Let us take u = ex and v = cotx




Putting the above obtained values in the formula:-


(uv)′ = u′v + uv′


(ex cotx)’ = ex× cotx + ex× -cosec2x


= excotx - excosec2x


= ex (cotx - cosec2x)


Ans) ex (cotx - cosec2x)


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