Answer :

Let f(x) = tan2x

We need to find the derivative of f(x) i.e. f’(x)


We know that,


…(i)


f(x) = tan2x


f(x + h) = tan2(x + h)


Putting values in (i), we get




Using:






[ sin A cos B – sin B cos A = sin(A – B)


& sin A cos B + sin B cos A = sin(A + B)]






Putting h = 0, we get





[ sin2x = 2sinxcosx]



= 2tanx sec2x



Hence, f’(x) = 2tanx sec2x


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