Q. 224.2( 5 Votes )

# Find the locus of the point, the sum of whose distances from the points A(4, 0, 0) and B(-4, 0, 0) is equal to 10.

Answer :

**Given:** Points are A(4, 0, 0) and B(-4, 0, 0)

**To find:** the locus of point P, the sum of whose distances from the given points is equal to 10, i.e. PA + PB = 10

Let the required point P(x, y, z)

**Formula used:**

The distance between any two points (a, b, c) and (m, n, o) is given by,

Therefore,

The distance between P(x, y, z) and A(4, 0, 0) is PA,

Distance between P(x, y, z) and B(-4, 0, 0) is PB,

According to question:

PA + PB = 10

Squaring both sides:

Squaring both sides:

⇒ 16x^{2}+ 625 – 100x = 25x^{2}+ 400 + 200x + 25y^{2} + 25z^{2}

⇒ 16x^{2}+ 625 – 100x – 25x^{2}– 400 – 200x – 25y^{2} – 25z^{2} = 0

⇒ -9x^{2} – 25y^{2} – 25z^{2} – 300x + 225 = 0

⇒ 9x^{2} + 25y^{2} + 25z^{2} + 300x – 225 = 0

Hence **locus of point P is 9x ^{2} + 25y^{2} + 25z^{2} + 300x – 225 = 0**

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