# Find the coordinates of the foot of the perpendicular drawn from the point A(1, 8, 4) to the line joining the points B(0, -1, 3) and C(2, -3, -1).

Given: perpendicular drawn from point A (1, 8, 4) to line joining points B (0, -1, 3) and C (2, -3, -1)

To find: foot of perpendicular

Formula Used: Equation of a line is

Vector form: Cartesian form: where is a point on the line and with b1 : b2 : b3 being the direction ratios of the line.

If 2 lines of direction ratios a1:a2:a3 and b1:b2:b3 are perpendicular, then a1b1+a2b2+a3b3 = 0

Explanation:

B (0, -1, 3) is a point on the line.

Therefore, Also direction ratios of the line are (0 - 2) : (-1 + 3) : (3 + 1)

-2 : 2 : 4

-1 : 1 : 2

So, equation of the line in Cartesian form is Any point on the line will be of the form (-λ, λ - 1, 2λ + 3)

So the foot of the perpendicular is of the form (-λ, λ - 1, 2λ + 3)

The direction ratios of the perpendicular is

(-λ - 1) : (λ – 1 - 8) : (2λ + 3 - 4)

(-λ - 1) : (λ – 9) : (2λ – 1)

From the direction ratio of the line and the direction ratio of its perpendicular, we have

-1(-λ - 1) + λ – 9 + 2(2λ – 1) = 0

λ + 1 + λ – 9 + 4λ – 2 = 0

6λ = 10 So, the foot of the perpendicular is Rate this question :

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