Q. 7 F5.0( 1 Vote )

# Find the equation

Given: Foci are (2, 0) and (-2, 0) and eccentricity is

To find: equation of the hyperbola

Formula used:

The standard form of the equation of the hyperbola is,

Center is the mid-point of two foci.

Distance between the foci is 2ae and b2 = a2(e2 – 1)

The distance between two points (m, n) and (a, b) is given by

Mid-point theorem:

Mid-point of two points (m, n) and (a, b) is given by

Center of hyperbola having Foci (2, 0) and (-2, 0) is given by

= (0, 0)

The distance between the foci is 2ae, and Foci are (2, 0) and (-2, 0)

b2 = a2(e2 – 1)

The equation of hyperbola:

45x2 – 36y2 – 80 = 0

Hence, required equation of hyperbola is 45x2 – 36y2 – 80 = 0

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

The eccentricity RD Sharma - Mathematics

The latus-rectum RD Sharma - Mathematics

The eccentricity RD Sharma - Mathematics

The foci of the hRD Sharma - Mathematics

The equation of tRD Sharma - Mathematics

The equation of tRD Sharma - Mathematics

The eccentricity RD Sharma - Mathematics

A point moves in RD Sharma - Mathematics

The equation of tRD Sharma - Mathematics

The length of theRD Sharma - Mathematics