Q. 6 C5.0( 1 Vote )

Find the equation

Answer :

Given: conjugate axis is 5 and passes through the point (3, -2)


To find: the equation of the hyperbola


Formula used:


For hyperbola:



Conjugate axis is 2b


Therefore




The equation of hyperbola is:



Since it passes through (3, -2)










The equation of hyperbola:








Hence, required equation of hyperbola is 65x2 – 36y2 = 441


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