Answer :

Given relations are:

3lm–4ln+mn=0 ……(1)


l=–2m–3n ……(2)

Substituting (2) in (1) we get,

3(–2m–3n)m –4(–2m–3n)n +mn =0

3(–2m2–3mn) –4(–2mn–3n2) +mn=0





Substituting the values of (3) in (2) we get,

For the 1st line:

The Direction Ratios for the 1st line is .

For the 2nd line:

The Direction Ratios for the 2nd line is .

We know that the angle between the lines with direction ratios proportional to (a1,b1,c1) and (a2,b2,c2) is given by:

Using the above formula we calculate the angle between the lines.

Let be the angle between the two lines given in the problem.

The angle between two lines is .

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