Q. 93.9( 10 Votes )
The vertices of a triangle ABC are A(3, 2, 0), B(5, 3, 2) and C(-9, 6, -3). The bisector AD of ∠ A meets BC at D, find the fourth vertex D.
Answer :
The given co-ordinates: A(3, 2, 0), B(5, 3, 2) and C(-9, 6, -3)
Now, AB 
= 3
Also, AC 
Now, we have, 
By the property of internal angle bisector,
Therefore, 
Applying the section formula, we get,
D(x, y, z) 
D(x, y, z) 
Answer.
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