Answer :

Consider, C(0,y,0) point which lies on y axis and is equidistant from points A(3, 1, 2) and B(5, 5, 2).


AC = BC



Squaring both sides,


=


9+ y2 -2y +1 + 4 = 25 + y2 -10y +25 + 4


8y = 40


Y = 5


The point C is (0,5,0).


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