Answer :

Given: A(7, p, 2) and B(q, -2, 5), line segment joining these two points will be, AB = (q-7)i + (-2-p)j + 3k


And the line segment joining C(2, -3, 5) and D(-6, -15, 11) will be, CD = -8i – 12j + 6k


Then, the angle between these two line segments will be 0 degree. So, the cross product will be 0.


ABCD = 0


ð ((q-7)i + (-2-p)j + 3k)( -8i – 12j + 6k) = 0


Thus, solving this we get,


p = 4 and q = 3


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