Q. 10 E5.0( 4 Votes )

# Find the ce

Given that we need to find the centre, lengths of axes, eccentricity and foci of the ellipse 4x2 + 16y2 - 24x - 32y - 120 = 0. 4x2 + 16y2 - 24x - 32y - 120 = 0

4(x2 - 6x + 9) + 16(y2 - 2y + 1) - 172 = 0

4(x - 3)2 + 16(y - 1)2 = 172  Comparing with the standard form Centre = (p,q) = (3,1)

Here a2>b2

eccentricity(e) =     Length of the major axis 2a = 2( ) = Length of the minor axis 2b = Foci = (p±ae,q)

Foci = Foci = Rate this question :

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