Q. 145.0( 1 Vote )

# Using vector meth

Given Points :

A ≡ (4, 5, 1)

B ≡ (0, -1, -1)

C ≡ (3, 9, 4)

D ≡ (-4, 4, 4)

To Prove : Points A, B, C & D are coplanar.

Formulae :

4) Position Vectors :

If A is a point with co-ordinates (a1, a2, a3)

then its position vector is given by, 5) Vectors :

If A & B are two points with position vectors ,

Where,  then vector is given by,  6) Scalar Triple Product:

If   Then, 7) Determinant : For given points,

A ≡ (4, 5, 1)

B ≡ (0, -1, -1)

C ≡ (3, 9, 4)

D ≡ (-4, 4, 4)

Position vectors of above points are,    Vectors are given by,   ………eq(1)   ………eq(2)   ………eq(3)

Now, for vectors     = 4(15) – 6(21) + 2(33)

= 60 – 126 + 66

= 0 Hence, vectors are coplanar.

Therefore, points A, B, C & D are coplanar.

Note : Four points A, B, C & D are coplanar if and only if Rate this question :

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