Q. 3 E3.8( 6 Votes )

Find the equation

Answer :

We need to find the equation of the parabola whose focus is (0, 0) and vertex is the point of intersection of lines x + y = 1 and x - y = 3.



On solving the lines, we get the vertex (2, - 1).


We know that the line passing through focus and vertex i.e., the axis is perpendicular to the directrix and vertex is the midpoint of focus and point that lies at the intersection of axis and directrix.


Slope of axis (m1) =



We know that the products of the slopes of the perpendicular lines is - 1.


Let us assume m2 be the slope of the directrix.


m1.m2 = - 1



m2 = 2


Let us find the point on directrix.




x = 4 and y = - 2


The point on directrix is (4, - 2).


We know that the equation of the lines passing through (x1, y1) and having slope m is y - y1 = m(x - x1)


y - (- 2) = 2(x - 4)


y + 2 = 2x - 8


2x - y - 10 = 0


Let us assume P(x, y) be any point on the parabola.


We know that the point on the parabola is equidistant from focus and directrix.


We know that the distance between two points (x1, y1) and (x2, y2) is .


We know that the perpendicular distance from a point (x1, y1) to the line ax + by + c = 0 is .


SP = PM


SP2 = PM2





5x2 + 5y2 = 4x2 + y2 - 40x + 20y - 4xy + 100


x2 + 4y2 + 4xy + 40x - 20y - 100 = 0


The equation of the parabola is x2 + 4y2 + 4xy + 40x - 20y - 100 = 0.


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